Question

[(x的平方-9分之x+3)+(6+x-x的平方分之x)乘(4x-6分之3-x)

Answer 1

[ (x+3) / (x² - 9) + x / (6+x - x²) ] * (3-x) / (4x - 6)

= [ 1/(x-3) - x / (x+2)(x-3) ] * (3-x) / (4x - 6)

= 2 / [(x+2)(x-3) ] * (3- x) / [ 2(2x - 3)]

= - 1 / [ (x+2) (2x - 3) ]