Question

氨的催化氧化反应4NH3+5O2=4NO+6H2O,在容积为5L的密闭容器中进行,0.5min后,NO的物质的量增加了0

Answer 1

0.5min后,NO的物质的量增加了0.3mol 那么

NH3 = 0.3/4*4=0.3mol

O2 = 0.3/4*5=0.375mol

H2O = 0.3/4*6=0.45mol

t（时间）=0.5*60=30s

v(O2)=0.375/30/5=0.0025mol/(L•s)

v(NO)=0.3/30/5=0.002mol/(L•s)

v(H2O)=0.45/30/5=0.003mol/(L•s)

v(NH3)=0.3/30/5=0.002mol/(L•s)

所以是 CD