Question

计算：2x^3y*[(3xy^2)^2)+(-4xy^3)*(-xy)] (ab^2)^3*(ab^2)^2

Answer 1

2x^3y*[(3xy^2)^2)+(-4xy^3)*(-xy)]

=2x^3y*[9x^2y^4+4x^2y^]

=2x^3y*13x^2y^4

=26x^5y^5

(ab^2)^3*(ab^2)^2

=a^2b^6*a^2b^4

=a^4b^10

(3.6*10^4)*(5*10^7)+(3*10^5)*(9*10^6)

=18*10^11+27*10^11

=(18+27)*10^11

=45*10^11

=4.5*10^12

(3x^2+1/2y-2/3y^2)*(-1/2xy)^3

=(3x^2+1/2y-2/3y^2)*(-1/8x^3y^3)

=-3/8x^5y^3-1/16x^3y^4+1/12x^3y^5