设 铁体积 = 铜体积= 1V, 则 总体积=2V,
纯铜密度8.9, 钝铁 7.86,
总质量= m铁+m铜 = 7.86V + 8.9V = 16.76V,
合成密度 = 总质量 / 总体积,
= 16.76V / 2V
= 8.38 (g/cm^3).
设 铁体积 = 铜体积= 1V, 则 总体积=2V,
纯铜密度8.9, 钝铁 7.86,
总质量= m铁+m铜 = 7.86V + 8.9V = 16.76V,
合成密度 = 总质量 / 总体积,
= 16.76V / 2V
= 8.38 (g/cm^3).