y=asinx+acosx=√2*a(√2/2sinx+√2/2cosx) =√2*a(cosπ/4sinx+cosxs
1个回答
y=asinx+acosx==√2*asin(x+π/4)
当a>0时,y最大值为√2*a,最小值为-√2*a
值域:[-√2*a,√2*a]
当a
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