Question

已知a>=0,函数f(x)=(x^2-2ax)e^x,设在f(x)在区间[-1,1]上是单调函数,求a的取值范围.

Answer 1

f(x)=(x²-2ax)e^x

f'(x)=(x²-2ax+2x-2a)e^x

令g(x)=x²+(2-2a)x-2a

g(0)=-2a