C
ΔH=反应物的键能之和-生成物的键能之和,
H 2(g)+
Cl 2(g)=HCl(g)的ΔH=(436 kJ·mol - 1+243 kJ·mol - 1)/2-431 kJ·mol - 1=-91.5 kJ·mol - 1,所以,A项对,C项错;B项反应的ΔH=436 kJ·mol - 1+243 kJ·mol - 1-2×431 kJ·mol - 1=-183 kJ·mol - 1,对;D项反应的ΔH=2×431 kJ·mol - 1-(436 kJ·mol - 1+243 kJ·mol - 1)=+183 kJ·mol - 1,对。