∵x 2-5x-2000=0
∴x 2-5x=2000
(x-2) 3 - (x-1) 2 +1
x-2 =
(x-2) 3 - x 2 +2x-1+1
x-2 =
(x-2) 3 -x(x-2)
x-2 =(x-2) 2-x=x 2-5x+4=2004
故选D
∵x 2-5x-2000=0
∴x 2-5x=2000
(x-2) 3 - (x-1) 2 +1
x-2 =
(x-2) 3 - x 2 +2x-1+1
x-2 =
(x-2) 3 -x(x-2)
x-2 =(x-2) 2-x=x 2-5x+4=2004
故选D