Question

函数f(X)=x^5+ax^3+bx+1,若f(100)=1则f(-100)等于多少

Answer 1

f(100)+f(-100)

=100^5+a*100^3+b*100+1+(-100^5-a*100^3-b*100+1)

=2

所以 f(-100)=2-1=1