(m-n)^7/(n-m)^6+(-n-m)^3/(m+n)^2
3个回答
(m-n)^7/(n-m)^6+(-n-m)^3/(m+n)^2
=(m-n)^7/(m-n)^6-(m+n)^3/(m+n)^2
=(m-n)-(m+n)
=m-n-m-n
=-2n
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