(1)W1=Pt1=0.5kw×5h=2.5kw•h
则电能表的示数为760.2kw•h+2.5kw•h=762.7kw•h
(2)电能表转80转消耗的电能为:W2=[80/3000]kw•h=9.6×104J
用电器的实际功率为P2=
W2
t2=
9.6×104J
180s=533.3W.
答:(1)该用电器连续工作5h后,该电能表的示数为762.7kw•h.(2)接入电路的用电器实际功率应为533.3W.
(1)W1=Pt1=0.5kw×5h=2.5kw•h
则电能表的示数为760.2kw•h+2.5kw•h=762.7kw•h
(2)电能表转80转消耗的电能为:W2=[80/3000]kw•h=9.6×104J
用电器的实际功率为P2=
W2
t2=
9.6×104J
180s=533.3W.
答:(1)该用电器连续工作5h后,该电能表的示数为762.7kw•h.(2)接入电路的用电器实际功率应为533.3W.