已知弧长为C=11500,拱高为H=2000,求弦长L?
弧半径为R.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=8000
R1=7905.78
R2=7907.8
R3=7907.8
R=7907.8
L=(R^2-(R-H)^2)^0.5
=(7907.8^2-(7907.8-2000)^2)^0.5
=5256.54
有了弧半径用CAD就可以画了!
CAD作图,已知弧长为11500,拱高为2000,求弦长,如何用CAD画出来,