Question

已知a.b.c满足(1)5(a+3)^2+2|b-2|=0,(2)1/3x^2-ay^1+b+c是七次单项式,求整式a^

Answer 1

（1）a+3=0;

a=-3;

b-2=0;

b=2;

（2）2-a+1+b+c=7;

c=4+a-b=-1;

a^2b-[a^2b-(2abc-a^2c-3a^2b)-4a^2c]-abc

=a²b-a²b+2abc-a²c-3a²b+4a²c-abc;

=-a²b-2a²b+abc+3a²c

=-9×2-2×9×2+(-3)×2×(-1)+3×9×(-1)

=-18-36+6-27

=-75;

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