Question

若2a^2+4ab+4b^2-2a+1=0,求b^a

Answer 1

2a^2+4ab+4b^2-2a+1

=a^2-2a+1+a^2+4ab+4b^2

=(a-1)^2+(a+2b)^2

=0

说明a-1=0 a+2b=0

所以 a=1 b=-1/2

b^a=(-1/2)^1=-1/2