Question

常温下,在27.5水中溶解12.5CuSO4·5H2O,敲好达到宝盒,该溶液密度为1.21g/cm3.

Answer 1

1

n(CuSO4)=12.5g/(250g/mol)

=0.05mol

因为阴阳离子是Cu 2+ 、SO4 2-

所以n(阴阳离子)=0.05mol*2=0.1mol

2

c=1000ρω/M （ρ是溶液密度,ω是质量分数）

=1000*1.21g/mL * [0.05mol*160g/mol /(27.5g+12.5g)] / 160

=1.5125mol/L

3

n(CuSO4)=1.5125mol/L * 0.02L

=0.03025mol

设稀释后V L

V*1=0.03025

V=0.03025L

=30.25mL

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