Question

已知三角形ABC的顶点B(2,1),C(-6,3),其垂心为H(-3,2),求点A的坐标

Answer 1

k(BC)=(3-1)/(-6-2)=-1/4

k(AH)=4

AH:y-2=4(x+3)

y=4x+14.(1)

k(CH)=-1/3

k(AB)=-1/k(CH)=3

AB:y-1=3(x-2)

y=3x-5.(2)

解方程组(1),(2),得

4x+14=3x-5

x=-19,y=-62

点A的坐标(-19,-62)