1/(|x3)+1/(3x5)+|/(5x7)+,..+1/(2n-1)(2n+1)
=[1/2]x[1/1-1/3+1/3-1/5+1/5-1/7+.+1/(2n-1)-1/(2n+1)]
=[1/2]x[1-1/(2n+1)]
=n/(2n+1)
=17/35
=>
n=17
1/(|x3)+1/(3x5)+|/(5x7)+,..+1/(2n-1)(2n+1)=17/35,求n的值
2个回答
相关问题
-
找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
-
找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
-
若1/(1*3)+1/(3*5)+1/(5*7)+.+1/[(2n-1)(2n+1)]的值为17/35.
-
1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)的值为17/35怎么算
-
Sn=1+3x+5x^2+7x^3+…+(2n-1)*x^(n-1)；
-
vb求和,求sin(x)=x/1-x^3/3!+x^5/5!- …… (-1)^(n-1)* x^(2*n-1)/(2n
-
求1+1/2x1/3+1/2^2x1/5+1/2^3x1/7+1/2^n⑴x1/2n⑴的值是多少的方法
-
用裂项法求值1/1x2x3 + 1/2x3x4 +1/3x4x5 + … + 1/n(n+1)(n+2)1/1x3 +
-
求和：Sn=1-3x+5x^2-7x^3+.+(2n+1)(-x)^n(n属于N*)
-
找规律算出N的数学题目1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)=17/35 解出n的值