整式的乘法(要过程)2ab(5a^2b+3ab^2)(3分之2ab^2-2ab)*2分之1ab5X(2x^2-3x+4)

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  • 2ab(5a^2b+3ab^2)=10a^3b^2+6a^2b^3

    (3分之2ab^2-2ab)*2分之1ab=1/3a^2b^3-a^2b^2

    5X(2x^2-3x+4)=10x^3-15x^2+20x

    -2a^2(2分之1ab+b^2)=-a^3b-2a^2b^2

    -6x(x-3y)=-6x^2+18xy

    (3分之2x^2-6xy)*2分之1xy^2=1/3x^3y^2-3x^2y^3

    x(y-z)+y(z-x)-z(y-x)

    =xy-xz+yz-xy-yz+xz

    =0

    -x(x^2-x+1)+(-x)^2*(x^2+2x-1)

    =-x^3+x^2-x-x^4-2x^3+x^2

    =-x^4-3x^3+2x^2-x

    先化简,再求值:x^2(x^2-xy+y)-x*(x^3-2x^2y+xy-1),

    |X-2|+(y+4分之1)^2=0

    则x-2=0 x=2

    y+1/4=0 y=-1/4

    x^2(x^2-xy+y)-x*(x^3-2x^2y+xy-1)

    =x^4-x^3y+x^2y-x^4+2x^3y-x^2y+x

    =x^3y+x

    =2^3*(-1/4)+2

    =-2+2

    =0

    已知:xy^2=-2,求-xy(x^3y^7-3x^2y^5-y)的值

    -xy(x^3y^7-3x^2y^5-y)

    =-x^4y^8+3x^3y^6+xy^2

    =-(xy^2)^4+3(xy^2)^3+xy^2

    =-(-2)^4+3×(-2)^3-2

    =-16-24-2

    =-42