证明:
∵BE⊥AD,CF⊥AD
∴ 角EBA=角FCD=90°
∵AB=CD,AE=DF,角EBA=角FCD
∴△EBA=△FCD
∴角EAB=角FDC
∵AD为△EAD和△FDA的公共边
又∵AE=DF,角EAB=角FDC
∴△EAD=△FDA
∴AF=DE
证明:
∵BE⊥AD,CF⊥AD
∴ 角EBA=角FCD=90°
∵AB=CD,AE=DF,角EBA=角FCD
∴△EBA=△FCD
∴角EAB=角FDC
∵AD为△EAD和△FDA的公共边
又∵AE=DF,角EAB=角FDC
∴△EAD=△FDA
∴AF=DE