Question

[2^2=1]*[2^4=1]*[2^8=1][2^16=1]运算过程及结果

Answer 1

[2^2+1]*[2^4+1]*[2^8+1][2^16+1] 乘1/3(2^2-1)=1

=1/3(2^2-1)[2^2+1]*[2^4+1]*[2^8+1][2^16+1]

=1/3(2^4-1)*[2^4+1]*[2^8+1][2^16+1]

=...

=1/3(2^32-1)