已知抛物线y=ax2+bx+c的对称轴为直线x=2,且与x轴交于A、B两点,与y轴交于点C,其中A(1,0),C(0,-

2个回答

  • (1) 对称轴为直线x=2,y = a(x - 2)² + d

    x = 1,y = a + d = 0

    x = 0,y = 4a + d = -3

    a = -1,d = 1

    y = -(x - 2)² + 1 = -xy = -x² + 4x - 3 = -(x - 1)(x - 3)

    A(1,0),B(3,0)

    (2)

    ①△PBC面积与△ABC面积相等时,AB为共同的底,只须高相同,即P,C纵坐标相等

    -x² + 4x - 3 = -3

    x = 4 (舍去0)

    ②BC为角ACP的平分线

    AC的解析式:x - y/3 = 1,3x - y - 3 = 0

    设CP斜率为k,解析式y = kx - 3,kx - y - 3= 0

    B与二者距离相等:

    |9 - 0 - 3|/√(9 + 1) = |3k - 0 - 3|/√(k² + 1)

    3k² - 10k + 3 = 0

    (3k - 1)(k - 3) = 0

    k = 1/3 (舍去k = 3,此时CP与AC重合)

    直线CP的解析式:y = x/3 - 3