1/（a+1）-(a+3)/(a^2-1)*(a^2-2a+1)/(a^2+6a+9)
=1/(a+1)-(a+3)/(a+1)(a-1)*(a-1)²/(a+3)²
=1/(a+1)-1/（a+1）（a+3）
=(a+2)/(a+1)(a+3)
=（a+2）/a²+4a+3
=正负2根号3/11
其中a^2+4a-8=0
所以a²+4a=8
(a+2)²-12=0
a+2=正负2根号3
已知实数a满足a^2+4a-8=0,求1/a+1-a+3/a^2-1*a^2-2a+1/a^2+6a+9的值.
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