①3x^2=4x；
3x²-4x=0
x(3x-4)=0
x1=0,x2=4/3
②x（x-1）+3（x-1）=0;
(x-1)(x+3)=0
x1=1
x2=-3
③3（x-5）^2=2（5-x）;
3(x-5)²+2(x-5)=0
(x-5)[3(x-5)+2]=0
(x-5)(3x-13)=0
x1=5
x2=13/3
④3x^2-4x=2x;
3x²-4x-2x=0
3x²-6x=0
3x(x-2)=0
x1=0
x2=2
⑤x（x-6）=2（x-8）
x²-6x-2x+16=0
x²-8x+16=0
(x-4)²=0
x1=x2=4