ξ可能取值为2,3,4,5;
p(ξ=2)=4/120;
p(ξ=3)=16/120;
p(ξ=4)=36/120;
p(ξ=5)=64/120;
Eξ=2*(4/120)+3*(16/120)+4*(36/120)+5*(64/120)=13/3;
ξ可能取值为2,3,4,5;
p(ξ=2)=4/120;
p(ξ=3)=16/120;
p(ξ=4)=36/120;
p(ξ=5)=64/120;
Eξ=2*(4/120)+3*(16/120)+4*(36/120)+5*(64/120)=13/3;