Question

关于x的一元二次方程mx²-2mx+m+1=0有实数根,那么|m-3|+m的值为多少

Answer 1

mx²-2mx+m+1=0有实数根,有

△ = 4m² - 4m(m+1)≥0

-4m ≥ 0

m ≤ 0

∴ |m-3|+m = 3-m + m = 3