Question

(999..9)1999个9加1999...9(1999个9)的平方根怎样算?

Answer 1

999...9（1999个9）*999...9（1999个9）+1999...9（1999个9)

=999...9^2(1999个9)+1999...98(1999-1个9)+1

=999...9^2(1999个9)+2*999...9(1999个9)*1+1^2

=(999...9(1999个9)+1)^2

=1000...0^2(1999个0)

=1000...0(2*1999个0)