如图所示,求电路中合适的元件值

1个回答

  • 电压相量:U(相量)=50/√2∠π/4=50/√2∠45°(V).

    电流:i=400cos(10t+π/6)=400cos(-10t-π/6)=400sin(π/2+10t+π/6)=400sin(10t+2π/3).

    所以:I(相量)=400/√2∠2π/3=400/√2∠120°(A).

    因此,电路导纳为:Y=I(相量)/U(相量)=8∠75°=2.07055+j7.7274(S)=

    1/0.48296+1/(-j0.12941)(S).

    而电路导纳:Y=Y1+Y2=1/R+1/(-jXc),所以:R=0.48296(Ω)

    Xc=0.12941(Ω),同时Xc=1/(ωC),所以C=1/(ωXc).电路参数中ω=10

    所以:C=1/(10×0.12941)=0.77274(F).