1/[x(x^6+4)] = -(1/4)x^5/(x^6+4) +(1/4) (1/x)
∫dx/[x(x^6+4)]
=(1/4) ∫ [-x^5/(x^6+4) +(1/x)] dx
= (1/4) lnx - (1/24)∫ dln(x^6+4)
= (1/4) lnx - (1/24)ln(x^6+4) + C
dx除以x（x六次方＋4）积分你解答的第三步看不懂啊,－t五次方／1+4t六次方是怎么出来的
1/[x(x^6+4)] = -(1/4)x^5/(x^6+4) +(1/4) (1/x)
∫dx/[x(x^6+4)]
=(1/4) ∫ [-x^5/(x^6+4) +(1/x)] dx
= (1/4) lnx - (1/24)∫ dln(x^6+4)
= (1/4) lnx - (1/24)ln(x^6+4) + C