由放出的氢气量可知有0.2mol的钠与水反应.m=0.2mol×23g/mol=0.46g
4Na+O2==2Na2O
92 124
x 0.124
x=0.094g
NaOH%=(0.46+0.094)÷(9.463-0.022×18+0.584)×100%=5.56%
由放出的氢气量可知有0.2mol的钠与水反应.m=0.2mol×23g/mol=0.46g
4Na+O2==2Na2O
92 124
x 0.124
x=0.094g
NaOH%=(0.46+0.094)÷(9.463-0.022×18+0.584)×100%=5.56%