x∈[π/12,π/2]
-π/6≤2x-π/3≤2π/3
-1/2≤sin(2x-π/3)≤1
a>0时,当sin(2x-π/3)=1时,f(x)max=2a+b;当sin(2x-π/3)=-1/2时,f(x)min=-a+b
2a+b=1
-a+b=-5
解得a=2 b=-3
a
x∈[π/12,π/2]
-π/6≤2x-π/3≤2π/3
-1/2≤sin(2x-π/3)≤1
a>0时,当sin(2x-π/3)=1时,f(x)max=2a+b;当sin(2x-π/3)=-1/2时,f(x)min=-a+b
2a+b=1
-a+b=-5
解得a=2 b=-3
a