1/a-1 -4/a的平方-4,其中a=1/2
=1/(a-1)-4/(a^2-4)
=1/(a-1)-4/(a+2)(a-2)
=1/(a-1)-[1/(a-2)-1/(a+2)]
=1/(1-1/2)-[1/(1/2-2)-1/(1/2+2)]
=2-[-2/3-2/5]
=2+16/15
=46/15
4x的3次方+4x的2次方+x
=x(4x^2+4x+1)
=x(2x+1)^2
1/a-1 -4/a的平方-4,其中a=1/2
=1/(a-1)-4/(a^2-4)
=1/(a-1)-4/(a+2)(a-2)
=1/(a-1)-[1/(a-2)-1/(a+2)]
=1/(1-1/2)-[1/(1/2-2)-1/(1/2+2)]
=2-[-2/3-2/5]
=2+16/15
=46/15
4x的3次方+4x的2次方+x
=x(4x^2+4x+1)
=x(2x+1)^2