Question

设函数f(x)=x^2-2Inx,h(x)=1/3x^3-1/2x^2+mx+1,若函数g(x)=f(x)-h ’(x)

Answer 1

h'(x)=x^2-x+m

g(x)=x-2lnx-m

令g'(x)=1-2/x=0

x=2时g(x)极小值

g(2)=2-2ln2-m=0

g(3)=3-2ln3-m>=0

即2-2ln2