(1)f(x)=【1-sin(x-3π/2)+cos(x+π/2)+tan3π/4】/cosx
=【1-sin(x+π/2)+cos(x+π/2)-1】/cosx
=[-cos(-x)+sin(-x)]/cosx
=(1-cosx-sinx-1)/cosx=(-cosx-sinx)/cosx
求函数y=f(x)的定义域cosx≠0 ,x≠2kπ+π/2
（2）设tana=-4/3,
f(x)=(-cosx-sinx)/cosx
=-1-tanx
f(a)=-1-(-4/3)=1/3
已知函数f(x)=【1-sin(x-3π/2)+cos(x+π/2)+tan3π/4】/cosx
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