Question

若cosα+3sinα/6sinα-2cosα=2

Answer 1

（cosα+3sinα）/(6sinα-2cosα)=2

cosα+3sinα=(6sinα-2cosα)*2

5cosα=9sinα

tanα=5/9

sin2^α+cos2^α=1

所以cosα=9/(106)^0.5 sinα=5/(106)^0.5

sin2^α+3sinαcosα-2cos2^α=-1/53