Question

解方程：abc=1求 ab+a+1分之2ax+bc+b+1分之2bx+ca+c+1分之2cx=1

Answer 1

ab+a+1分之2ax+bc+b+1分之2bx+ca+c+1分之2cx=1

2ax/(ab+a+1)+2bx(bc+b+1)+2cx/(ca+c+1)=1

2x[a/(ab+a+1)+ab/(abc+ab+a)+abc/(abca+abc+ab)]=1

2x[a/(ab+a+1)+ab/(1+ab+a)+1/(a+1+ab)]=1

2x[(a+ab+1)/(ab+a+1)]=1

2x=1

x=1/2.

方程的解为：x=1/2.