4x^2+y^2+20x+6y+34=0,求x,y的值
3个回答
4x^2+y^2+20x+6y+34=0,
4x^2+20x+25+y^2+6y+9=0,
(2x+5)^2+(y+3)^2=0
2x+5=0,y+3=0
x=-5/2,y=-3
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