如图所示,有一边长为5cm的正方形ABCD和等腰三角形PQR,PQ= PR= 3cm,QR=8cm,点B、C、Q、R在同

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  • 等腰三角形PQR,PQ= PR= 3cm, QR=8cm,

    两腰的和小于底明显有误数据有误拟PQ=PR=5cm

    作△PRQ的高PH,则QH=8/2=4PQ=5

    ∴PH=3(勾股数)

    (1)因为当0≤t≤4时,S=S△GCQ

    ∴当t=3时

    QC=3GC/3=3/4GC=9/4

    S=1/2•3•9/4=27/8((cm^2))

    (2)因为当4≤t≤54时S=S△PQR-S△RG1C

    ∴当t=5时

    G1C/3=RC/RH=(8-5)/4

    ∴G1C=9/4

    S△RG1C=1/2•(8-5)•9/4=27/8

    S△PRQ=1/2•3•8=12

    ∴S=12-27/8=69/8((cm^2))

    (3)当5≤t≤8时S=S△ABC-S△RG1C-S△QG2B

    QB=t-5QB/4=G2B/3

    G2B=(3t-15)/4

    ∴S△QG2B=1/2•(t-5)•(3t-15)/4=3/8((t-5)^2)

    RC=8-tRC/4=G1C/3

    (8-t)/4=G1C/3⇒G1C=(24-3t)/4

    S△RG1C=1/2•(8-t)•(24-3t)/4=3/8((8-t)^2)

    S=12-3/8[((t-5)^2)+((8-t)^2)]