sin2θ=1/3,则tanθ+cotθ=
1个回答
sin2θ=2sinθcosθ=1/3
sinθcosθ=1/6
原式=sinθ/cosθ+cosθ/sinθ
=(sin²θ+cos²θ)/sinθcosθ
=1/(1/6)
=6
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