思路:
1/a
=(a+1)/[a(a+1)]
=a/[a(a+1)]+1/[a(a+1)]
=1/(a+1)+1/[a(a+1)]
可见:b=a+1,c=a(a+1)
例:
1/2=3/6=1/6+2/6=1/6+1/3
1/3=4/12=1/12+3/12=1/12+1/4
1/4=1/20+1/5
思路:
1/a
=(a+1)/[a(a+1)]
=a/[a(a+1)]+1/[a(a+1)]
=1/(a+1)+1/[a(a+1)]
可见:b=a+1,c=a(a+1)
例:
1/2=3/6=1/6+2/6=1/6+1/3
1/3=4/12=1/12+3/12=1/12+1/4
1/4=1/20+1/5