sin(π+α)=3/5,sin(α)=-3/5,α为第四象限角,cos(α-2π)=cos(α)=4/5
已知sin(π+α)=3/5,α为第四象限角,求cos(α-2π).
3个回答
相关问题
-
已知sinα=4/5 α为第四象限角,求cos(π-α)及cos2α
-
已知sinα=-3/5,α是第四象限角,求sin(π/4 -α),cos(π/4 +α),tan(α -π/4)的值
-
已知sinα=-3/5,且α是第四象限角,则tan[cos(3π-α)-sin(5π+α)]=
-
已知角α是第三象限角,cos(α-[3π/2])=[1/5],求:f(α)=sin(α−π2)cos(3π2+α)tan
-
已知sin(π+α)=4/5,且α是第四象限角,则cos(2π-α)=?
-
已知α是第四象限角 且cosα=5/13 求sin(α+π/4)/cos2α
-
cos(π+α)=-3/5,且α是第四象限角,则sin(-2π+α)=____________
-
已知α为第二象限角,f(α)=sin(5π−α)sin(32π+α)cos(32π−α)tan(−α−π)sin(3π+
-
已知角α是第三象限角,且f(α)=sin(π−α)cos(2π−α)tan(−α−π)tan(π+α)sin(−π−α)
-
已知α是第四象限角,且cos(α-π)=-1/2求sinα,cos(π/4+α)的值