求正整数解:10 ^n=79m+8(未知数:n与m)

1个回答

  • 令m=10a1+8

    则10^n=79(10a1+8)+8

    =790a1+79×8+8

    =790a1+640

    =10(79a1+64)

    10^(n-1)=79a1+64

    令a1=10a2+4

    则10^(n-1)=79(10a2+4)+64

    =790a2+79×4+64

    =790a2+380

    =10(79a2+38)

    10^(n-2)=79a2+38

    令a2=10a3+8

    则10^(n-2)=79(10a3+8)+38

    =790a3+79×8+38

    =790a3+670

    =10(79a3+67)

    10^(n-3)=79a2+67

    令a3=10a4+7

    则10^(n-3)=79(10a4+7)+67

    =790a4+79×7+67

    =790a4+620

    =10(79a4+62)

    10^(n-4)=79a4+62

    令a4=10a5+2

    则10^(n-4)=79(10a5+2)+62

    =790a5+79×2+62

    =790a5+220

    =10(79a5+22)

    10^(n-5)=79a5+22

    令a5=10a6+2

    则10^(n-5)=79(10a6+2)+22

    =790a6+79×2+22

    =790a6+180

    =10(79a6+18)

    10^(n-6)=79a6+18

    令a6=10a7+8

    则10^(n-6)=79(10a7+8)+18

    =790a7+79×8+18

    =790a7+650

    =10(79a7+65)

    10^(n-7)=79a7+65

    令a7=10a8+5

    则10^(n-7)=79(10a8+5)+65

    =790a8+79×5+65

    =790a8+460

    =10(79a8+46)

    10^(n-8)=79a8+46

    令a8=10a9+6

    则10^(n-8)=79(10a9+6)+46

    =790a9+79×6+46

    =790a9+520

    =10(79a9+52)

    10^(n-9)=79a9+52

    令a9=10a10+2

    则10^(n-9)=79(10a10+2)+52

    =790a10+79×2+52

    =790a10+210

    =10(79a10+21)

    10^(n-10)=79a10+21

    当a10=1时

    10^(n-10)=79+21=100=10^2

    即:n-10=2

    n=12

    m=(10^12-8)÷79=12658227848