Question

求最值 y=根号(2-x)+根号(x+1)

Answer 1

显然y>=0

y²=2-x+√(2-x)(x+1)+x+1

=3+√(-x²+x+2)

-x²+x+2=-(x-1/2)²+9/4

定义域2-x>=0,x+1>=0

-1