帮忙计算几道对数题

1个回答

  • 2.计算:(1)log(3)2/log(27)64=log(3)2/log(3)4

    =log(4)2

    =1/2.

    (2) 2^[4+log(2)3=2^[log(2)16+log(2)3]

    =2^log(2)48

    =48.

    25^[1/2log(5)27+2log(5)2]=5^[log(5)27+4log(5)2]

    =5^[log(5)27+log(5)16]

    =5^log(5)432

    =432.

    (3)0.064^(--1/3)--(--7/8)^0+[(--2)^3]^(--1/3)+0.01^1/2

    =1/0.4--1+(--2)^(--1)+0.1

    =2.5--1--0.5+0.1

    =1.1.