cos2x/【sin（x+π/4）sin（x-π/4）】
=2cos2x/[2sin（x+π/4）sin（x-π/4）]
=2cos2x/[cos(π/2)-cos2x]
=2cos2x/[-cos2x]
=-2
化简cos2x/【sin（x+π/4）sin（x-π/4）】=?
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