Question

请问一下方程m(x2-2x-3) n(x2-2x-3) c=0的四个解是什么呢?

Answer 1

原方程：mnc(x^2-2x-3)(x^2-2x-3)=0 条件：mnc ≠ 0

mnc[(x-1)^2-4]^2=0

这是4次方程有4个实根、且为双重根!

(x-1)^2=4 x-1 = ±2 x = 1 ± 2

即：

x1 = x3 = 3

x2 = x4 = -1