f(x) = x^5 +ax³+bx+1
f '(x) = 5x^4 + 3ax² +b =(x² -1)(5x²-b) = 0 (且b < 0)
即:5x^4 + b - 5x² - bx² = 0
所以:b =-5 -3a (1)
当f(1) - f(-1) = 4 即: (1...
f(x) = x^5 +ax³+bx+1
f '(x) = 5x^4 + 3ax² +b =(x² -1)(5x²-b) = 0 (且b < 0)
即:5x^4 + b - 5x² - bx² = 0
所以:b =-5 -3a (1)
当f(1) - f(-1) = 4 即: (1...