Al3+的物质的量为:n=a/27
Al2(SO4)3-----------------2Al
1mol 2mol
x=a/54mol a/27mol
原溶液中Al2(so4)3物质量的浓度:C=n/V=(a/54)/(v/1000)=1000a/54v
Al3+的物质的量为:n=a/27
Al2(SO4)3-----------------2Al
1mol 2mol
x=a/54mol a/27mol
原溶液中Al2(so4)3物质量的浓度:C=n/V=(a/54)/(v/1000)=1000a/54v