当x∈ [
3
2 ,2) 时,
C
3
2 8 =
8
3
2 =
16
3 ,当x→2时,[x]=1,所以
C x8 =
8
2 =4 ;
当[2,3)时,
C 28 =
8×7
2×1 =28 ,当x→3时,[x]=2,
C x8 =
8×7
3×2 =
28
3 ,
故函数C 8 x的值域是 (4,
16
3 ]∪(
28
3 ,28] .
故选D
当x∈ [
3
2 ,2) 时,
C
3
2 8 =
8
3
2 =
16
3 ,当x→2时,[x]=1,所以
C x8 =
8
2 =4 ;
当[2,3)时,
C 28 =
8×7
2×1 =28 ,当x→3时,[x]=2,
C x8 =
8×7
3×2 =
28
3 ,
故函数C 8 x的值域是 (4,
16
3 ]∪(
28
3 ,28] .
故选D