log8^9*log27^32
1个回答
log8^9*log27^32
=lg9/lg8*lg32/lg27
=2/3*lg3/lg2*5/3*lg2/lg3
=2/3*5/3
=10/9
相关问题
log(8)9-log(27)32的值,
计算:log27(32)×log64(27)+log9(2)×log4(√27)=
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
log9底根号32开六次方*(log2底3+log4底9+log8底27+log16底81+log32底243)
9+log√2 27)(log27 4+log3√3 8)
log27 4*log8 9
(log27^4)*(log8^9=
2log3^2-log3^(32/9)+log3^8
1.log3 3/log27 64 2.log8 9 log3 2
lg1/2-lg5/8+log25/2-log8 9*log27 8