Question

已知f(x)= 根号3cos平方wx+sinwxcoswx+a(w＞0,a∈R)

Answer 1

(1)f(x)=√(3)cos²(wx)+sin(wx)cos(wx)+a

=√(3)[1+cos(2wx)]/2+sin(2wx)/2+a

=sin(π/3)cos(2wx)+cos(π/3)sin(2wx)+a+√(3)/2

=sin(π/3+2wx)+a+√(3)/2

π/3+2w*(π/6)=-3π/2,

w=-11/2.

f（x)=sin(π/3-11x)+a+√(3)/2

(2)-π/3